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0=4.9x^2+2x-50
We move all terms to the left:
0-(4.9x^2+2x-50)=0
We add all the numbers together, and all the variables
-(4.9x^2+2x-50)=0
We get rid of parentheses
-4.9x^2-2x+50=0
a = -4.9; b = -2; c = +50;
Δ = b2-4ac
Δ = -22-4·(-4.9)·50
Δ = 984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{984}=\sqrt{4*246}=\sqrt{4}*\sqrt{246}=2\sqrt{246}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{246}}{2*-4.9}=\frac{2-2\sqrt{246}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{246}}{2*-4.9}=\frac{2+2\sqrt{246}}{-9.8} $
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